Solve LeetCode 704: Binary Search in JavaScript: while(left less than equals to right) → mid = (left + right) / 2 → adjust pointers based on comparison.
#leetcode #javascript #shorts #binarysearch
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Keywords:
leetcode 704
binary search
js coding short
shorts
two pointer js
o(log n)
search algorithm
js interview
dsa fundamentals
Hash tags:- #leetcode #javascript #dsa #coding #programming #reactjs
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